what is the formula of recoil velocity of a gun?????????

When a bullet is fired from a gun,the gun moves back,opposite to the direction of motion of the bullet.This backward motion of the gun is called recoil and the velocity with it moves back is called recoil velocity.Before firing the bullet,both the bullet and the gun are at rest.Hence,the total momentum is zero.After firing the bullet,the bullet moves forward with a large momentum and the gun moves backward with equal momentum.

Let m and M be the masses of the bullet and gun respectively.If v and V are the velocities of the bullet and gun respectively after the firing,then

0 = mv + MV

therefore V = - mv/M

This is the expression for recoil velocity of the gun.The negative sign indicates that the gun moves in a direction to that of the bullet

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m1u1+m2u2= m1v1+m2v2
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momentum of gun=momentum of  bullet
=mass*recoil velocity=mass *velocity of bullet
recoil velocity=mass*velocity of bullet/mass of gun
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M1=Mass of gun
M2=Mass of bullet
V= Velocity of gun = Recoil velocity
V2=VELOCITY OF BULLET

V1 = M2V2 / M1
 
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v2=(m1v​1)/m2
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-mv/M
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m1u1+m2u2=m1v1+m2v2
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m1u1 + m2u2/m1v1
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mass is measured out of the gravity or without the respect of gravity &weight is measured in the respect of gravity
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Newton's third law of motion states that if an unbalanced force works on a body it will accelerate in the direction of motion and it's velocity will directly proportional to applied force and inversely proportional to its mass
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Momentum of bullet =momentum of gun Mass*velocity of bullet=mass *recoil velocity
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Momentum
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What are the vedas what do they contain
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I don't know
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U=1.8 mls V=4.2 m/s t=1.2 s velocity change 1.2 sec=4.2-1.8=2.4 m/s velocity change in 1 sec=2.4 by 1.2=2 mls velocity change in 2 sec=2x2 = 4 mls
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Force=? Mass (m) = 2 kg Time (t) = 10 s Velocity is increased from 5 m/s to 10 m/s Acceleration (a) =v-u/t =10-5/10=0.5 m/s^2 Force=m*v =2*0.5=1 N
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MV = mv MV/m = v
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Please find this answer

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Recoil velocity= -(mass of bullet/mass of gun) x velocity of bullet
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*Some Popular Examples* 1) when you shake a branch the leaves get detached. 2) when you beat a carpet the dust particles come out. 3) when you are sitting in a car and it starts moving you lean backward. Vinay Kumar👌
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Nice drawing of gun..
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M:mass of gun
m:mass of bullet
V:final velocity of gun
v:final velocity of bullet

MU+mu=MV+mv
But initial velocity would be 0
MV+mv=0
mv=MV
v=MV/m
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mv/M=V
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Problem 2

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the recoil velocity of a gun is 5 metre per second
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5 metre per second
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_mv/M
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M1u1+m2u2=m1v1+m2v2
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MV?+mv?=MV?+mv?
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Please find this answer

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Please find this answer

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I don't know
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velocity=distance traveled/time taken
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When a bullet is fired from a gun,the?gunmoves back,opposite to the direction of motion of the bullet.This backward motion of the gun is called recoil and the velocity with it moves back is called recoil velocity.Before firing the bullet,both the bullet and the gun are at rest.Hence,the total?momentum?is zero.After firing the bullet,the bullet moves forward with a large momentum and the gun moves backward with equal momentum.

Let m and M be the masses of the bullet and gun respectively.If v and V are the velocities of the bullet and gun respectively after the firing,then

0 = mv + MV

therefore V = - mv/M

This is the expression for?recoil velocity?of the gun.The negative sign indicates that the gun moves in a direction to that of the bullet
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m1u1+m2u2= m1v1+m2v2
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MBUB+MGUG=MBVB+MGVG
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M1v1+ m2v2=m1u1+ m2u2
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Momentum of bullet = momentum of gun
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Please find this answer

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M1=Mass of gun
M2=Mass of bullet
V1?= Velocity of gun = Recoil velocity
V2=VELOCITY OF BULLET

V1?= M2V2?/ M1
?
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m1u1+m2u2 =m1v1+m2v2
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m1u1+m2u2=m1v1+m2v2
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mAuA+mBuB=MaVa+MbVb
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Let m and M be the mass of bullet and gun resp. and v and V be the velocity of the bullet and gun resp. After firing:

0=mv +MV
Therefore V = -mv/M
The negative sign indicates that the gun moves in the opposite direction to the speed of the bullet.
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Sorry i dont know this
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When a bullet is fired from a gun,the?gun?moves back,opposite to the direction of motion of the bullet.This backward motion of the gun is called recoil and the velocity with it moves back is called recoil velocity.Before firing the bullet,both the bullet and the gun are at rest.Hence,the total?momentum?is zero.After firing the bullet,the bullet moves forward with a large momentum and the gun moves backward with equal momentum.

Let m and M be the masses of the bullet and gun respectively.If v and V are the velocities of the bullet and gun respectively after the firing,then

0 = mv + MV

therefore V = - mv/M

This is the expression for?recoil velocity?of the gun.The negative sign indicates that the gun moves in a direction to that of the bullet
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m1=mass of gun
m2=mass of bullet

u1=inetial velocity of gun
u2=inetial velocity of bullet

v1=final velocity of gun
v2=final velocity of bullet
Therefore, m1?u1+m2?u2=m1?v1+m2?v2
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