Normal year has 52 weeks (365/7) + 1 extra day ie. 52 Sundays + 1 day which can be any of the seven days So probability of 53 Sundays === Probability of that day being a sunday = 1/7

OR

The year MUST start on a Sunday, so you have only one favorable chance out of a total of 7 possibilities - a probability of 1/7.

- 133

Normal year has 52 weeks (365/7) + 1 extra day ie. 52 Sundays + 1 day which can be any of the seven days So probability of 53 Sundays === Probability of that day being a sunday = 1/7

OR

The year MUST start on a Sunday, so you have only one favorable chance out of a total of 7 possibilities - a probability of 1/7.

SO PLEASE CLICK THUMBS UP AT RIGHT BOTTOM OF THIS PAGE NAA...

- 30

Total number of days in a leep year = 366

Total number of complete week in leap year = 52

Remaining days = 2

They would be ,

Mon, Tue

Tue, Wed

Wed, Thu

Thu, Fri

Fri, Sat

**Sat, Sun**

**Sun, Mon**

Total number of outcome = 7

Total number required outcome =2

Therefore, Required Probablity = 2/7.....!!!!.....

- 13

So, let us calculate the no. of weeks in an non leap year(it is the same for a leap year, but we actually want the remainder as we will see later)

7)365(52

35

(-)_____

15

14

(-)__

1

this means that there are 52 weeks(and hence 52 Sundays) in a non leap year and one extra day. Out of seven days, the probability that that extra day is Sunday=(no.of Sundays in a week)/Total no of days in the week

=1/7

Hence, the probability that a non leap year has 53 Sundays is 1/7

- -5

**Here is the answer to your query**

number of days in a non-leap year=365 days = 52 weeks and 1 day

Each week there is 1 Sunday , but here there is 1 day extra

That 1 day can be either{Sunday, monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

Therefore,Probability of getting that day a Sunday=1/7

Thus,Probability of getting 52 Sundays= 1,whereas getting 53 Sundays =1/7

HOPE IT HELPED YOU

THUMBS UP PLEASE...

number of days in a non-leap year=365 days = 52 weeks and 1 day

Each week there is 1 Sunday , but here there is 1 day extra

That 1 day can be either{Sunday, monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

Therefore,Probability of getting that day a Sunday=1/7

Thus,Probability of getting 52 Sundays= 1,whereas getting 53 Sundays =1/7

HOPE IT HELPED YOU

THUMBS UP PLEASE...

- 51

**Leap year has 366 days**

i.e 52weeks and 2days

Therefore, Sunday comes 52 times and 2 days is chance of probability

These two days can be either the following (sample space):

i.e 52weeks and 2days

Therefore, Sunday comes 52 times and 2 days is chance of probability

These two days can be either the following (sample space):

*Sunday, Monday*

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Saturday, Sunday

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Saturday, Sunday

n(s):- 7

**We saw that "**

__Sunday__" comes twice. So,P(getting Sunday):- 2/7

*GIVE IT A THUMBS UP GUYS!!!*- -1

It’s 1/7.

In any year,there’re atleast 52 weeks which accounts for 52*7=364 days.Now a non-leap year has 365 days i.e. 1 day extra.For this day possibilities will be {mon ,tue, wed, thu, fri, sat, sun}.

Thus total no. Of possibilities are 7,out of which there’s one possibility of getting 53 Sundays i.e. when the extra day is Sunday.

Now,

probability =total no. Of favourable outcomes/total possible outcomes

So,probability=1/7.

- 0

366 days = 52 weeks alnd 2 days

So there are 53 sundays in leap year

Remaining 2 days can be-

1)sunday and monday

2)monday and tuesday

3)tuesday and wednesday

4)wednesday and thursday

5)thursday and friday

6)friday and saturday

7)saturday and sunday

So;no. Of events= 7

No.of favourable events=2

P(E)= 2/7

- 0

**1 / 7**.

- -1

OR

The year MUST start on a Sunday, so you have only one favorable chance out of a total of 7 possibilities - a probability of 1/7.

- 2