What is the probability that there are 53 Sundays in a leap year a) 1 / 6 b) - Maths - Probability

Question

What is the probability that there are 53
Sundays in a leap year ?
a) 1 / 6 b) 2 / 7 c) 3 / 8 d) 4 / 9
Is there any way or trick to find the
particular number of days given in this question or for any
question(its major use is in MAT),if it is then tell me that trick
?

Gursheen kaur. · Accepted Answer

In a Leap Year, there are 366 Days

In 366 Days = 52 Weeks and 2 Days

Thus,

A Leap Year has always 52 Sundays

The Remaining 2 Days can be :

(i) Sunday & Monday

(ii) Monday & Tuesday

(iii) Tuesday & Wednesday

(iv) Wednesday & Thursday

(v) Thursday & Friday

(vi) Friday & Saturday

(vii) Saturday & Sunday

Now, it is clear that there are 7 Elementary events associated
Let A be the event that a Leap Year has 53 Sundays

The event A will happen if the last two days of the leap year are
either Sunday & Monday or Saturday & Sunday

Total no of outcomes= 7

Favorable Outcomes = 2

Required Probability = 2/7

What is the probability that there are 53 Sundays in a leap year ? a) 1 / 6 b) 2 / 7 c) 3 / 8 d) 4 / 9 Is there any way or trick to find the particular number of days given in this question or for any question(its major use is in MAT),if it is then tell me that trick ?

What is the probability that there are 53 Sundays in a leap year ?

a) 1 / 6 b) 2 / 7 c) 3 / 8 d) 4 / 9

Is there any way or trick to find the particular number of days given in this question or for any question(its major use is in MAT),if it is then tell me that trick ?