what offer did the author gives of electing taking the road

Dear Student
Here is the answer to your question.

 

Any positive integer ending with the digit 0 is divisible by 5 and so its prime factorization must contain the prime number 5.

4ⁿ = (2²)ⁿ  = 2²ⁿ = 2*2 *2 *2 *2 ..... 2n terms

 

 

The prime numbers in the factorization of 4ⁿ are 2 only. 5 does not occur in the prime factorization of 4ⁿ.

 

∴ 4ⁿ does not end with the digit 0 for any natural number n.

 

Regards