What torque acts on a 40 turn coil of 100 cm2 area carrying a current of 10 A held with its axis at right angles to magnetic field of flux density 0.2 T and plane of the coil parallel to the field ???
torque = NBIAsin(x)
x=90 degree
so , T= 40 * 100^2 * (10^-2)^2 *0.2
T=0.8 Nm
HOPE IT HELPS !!!
x=90 degree
so , T= 40 * 100^2 * (10^-2)^2 *0.2
T=0.8 Nm
HOPE IT HELPS !!!