What will the density of the stone be if the weight of the stone is 15 gramsand is put in a 4ml of water.After putting the stone the water level increased to 7ml.
Given,
Mass of the stone = 15 g = 0.015 kg
Weight of the stone in air = 0.015 kg x 9.8 kgm/s2
= 0.147 N
After putting the stone the water level increased to 7 ml which was initially 4 ml.
Since density of water = 1 g/ml,
Mass of water displaced = 3 g = 0.003 kg
Loss of weight of stone in water = weight of water displaced
= 0.003 x 9.8 kgm/s2
= 0.0294 N
Therefore,
Weight of stone in water = Wt. of stone in air - loss of weight
= 0.147 - 0.0294 = 0.1176 N
Hence,
Density of the stone = Wt. of stone in air / (Wt. of stone in air - Wt. of stone in water)
= 0.147 / (0.147-0.1176)
= 5 g/cm3
Mass of the stone = 15 g = 0.015 kg
Weight of the stone in air = 0.015 kg x 9.8 kgm/s2
= 0.147 N
After putting the stone the water level increased to 7 ml which was initially 4 ml.
Since density of water = 1 g/ml,
Mass of water displaced = 3 g = 0.003 kg
Loss of weight of stone in water = weight of water displaced
= 0.003 x 9.8 kgm/s2
= 0.0294 N
Therefore,
Weight of stone in water = Wt. of stone in air - loss of weight
= 0.147 - 0.0294 = 0.1176 N
Hence,
Density of the stone = Wt. of stone in air / (Wt. of stone in air - Wt. of stone in water)
= 0.147 / (0.147-0.1176)
= 5 g/cm3