When a bird of weight W sits on a stretched wire,the tension T in the wire is A)>W/2 B) =W C)<W D) None of these . Give reasons Share with your friends Share 7 Vikas answered this In the above figure we have decomposed the tension in the string along the horizon "sx" and the vertical "sy". as you can see from the figure sx+sy =-mg ,for the wire to hold the bird weight.therefore the y component sy of the tension "s" in the string must be -12mg=12W where W =-mg since the tension "s" works at an angle to the vertical, it is only a certainpercentage of it which counter acts the weight W of the bird. at an anglesuch as in the diagram, s>W2, however if we place the poles together and give the wire more slack the angle between the vertical and the tensions will decrease ,that means component of s will increase resulting in s not having to be as greatas angle between the vertical and s is greater.If the poles are separated by some distance then it is impossible for the angle between s and sy to become 0, thus s will always be greater than sy and since sy=12w ,s>12wso A will be the answer -23 View Full Answer