When boron is fused with NaOH, products formed are

a) Na2B4O7 and H2

b) NaBO2 and H2

c) Na3BO3 and H2

d) B2O3 and H2

Kindly answer sir/mam

The correct answer is c.
B + 6NaOH  2Na3BO3 + 3H2

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