whenever a photon by hydrogen in  Balmer  series IT IS FOLLOWED BY ANOTHER PHOTON IN LYMAN  series what wavelength does this later photon correspond to

Dear Student,

Please find below the solution to the asked query.

Balmer series is obtained when an electron drops from a higher energy level to the second energy level. Thus, this electron makes another transition from second level to the first level which comes under Lyman series.

So, the wavelength associated with the photon of Lyman series will be:

$$\begin{gathered} \frac{1}{\lambda } = 1.097 \times {10}^7 (\frac{1}{1^2}-\frac{1}{2^2}) \\ = 1.097 \times {10}^7 (1-\frac{1}{4}) \\ = 1.097 \times {10}^7 \times \frac{3}{4} \\ = 0.82275 \times {10}^7 m^{-1} \\ So, \\ \lambda = \frac{1}{0.82275 \times {10}^7}m \\ = 1.22 \times {10}^{-7} m \\ = 122 \times {10}^{-9} m \\ = 122 nm \end{gathered}$$

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