which has he maximum volume of S.T.P and why?

(a) 1.5 * 10²³ molecules of CO₂

(b) 1g of H₂

(c) 4g of O₂

(d) 16 g SO₃

Dear student, the correct option is (c) i.e 4g of O₂ gas.

We know as STP, 1 mole of gas occupies 22.4 L volume. 

(a) 1 mole → 22.4L

6.023 × 10²³ molecule → 22.4 L

1.5 × 10²³ molecule → 5.57 L.

Hence 1.5 × 10²³ molecule of CO₂ gas occupies 5.57 L Volume

(b) 1 mole → 22.4 L

2g of hydrogen  → 22.4 L

1g of hydrogen  → 11.2 L

Hence H₂ gas occupies 11.2L volume

(c)  1 mole → 22.4 L

32g of Oxygen occupies  → 22.4 L

4 g of Oxygen occupies  → 2.8 L

(d)  1 mole → 22.4 L

80 g of SO3 occupies  → 22.4 L

16 g of SO3 occupies  → 4.48 L

Hence 16 g of SO3 gas occupies 4.48 L volume.