Which term of the AP is 6,19,32,45..........will be 143 more than its 34th term.

AP = 6, 19, 32

a = 6

d = 19 - 6 = 13

Let the required term be a_n

Given,

a_n = a₃₄ + 143

a + (n - 1)d = a + 33d + 143

13(n - 1) = 572

n - 1 = 44

n = 45

So, 45^th term of this AP will be 143 more than its 34^th term