Which term of the series ( 28−16𝑖)( 27−14𝑖)( 26−12𝑖) +⋯ is (i) purely real (ii) purely imaginary.
Clearly the given sequence forms an A.P. with
first term (a) = 28 - 16i and common difference (d) = -1 + 2i
⇒ an = a + (n - 1)d = 28 - 16i + (n - 1)(-1 + 2i) = 28 - 16i - n + 2ni +1 - 2i = (29 - n) + 2(n - 9)i
(1)
For this term to be purely real its imaginary part should be equal to zero
⇒ 2(n - 9) = 0
⇒ n - 9 = 0
⇒ n = 9
Hence required term is 29 - 9 = 20
(2)
For this term to be purely imaginary its real part should be equal to zero
⇒ 29 - n = 0
⇒ n = 29
Hence required term is 2(29 - 9)i = 40i