whoever answers gets a thumps up plzz answer.... (abhinav vema plzz help)

1. divide 184 into two parts such that one - third of one part may exceed one - seventh of the another part by 8
2. a sum of rs 800 is in the form of denominations of rs 10 rs 20.if the total number of notes is 50..find the numbers of notes of each type

answers : 1. 72,112 2. 10 rupees 20 notes and 20 rupees 30 notes

@verma.kirti111; correctly answered the question. Good effort. Keep it up.

The solution of 2^nd part is as follows:

2. Let there be x notes of Rs 10.

Total number of notes = 50.

∴ Number of notes of Rs 20 = (50 – x)

Total sum of money = Rs 800

∴ 10x + 20 (50 – x) = 800

⇒ 10x + 1000 – 20x = 800

⇒– 10x = 800 – 1000

⇒ – 10x = – 200

⇒ x = 20

∴ 50 – x = 50 – 20

 = 30

So, there are 20 notes of Rs 10 and 30 notes of Rs 20.