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why is the formula of ch4 in excited state 1s2 2s1 2p1x 2p1y 2p1z ?

In CH​4 molecule, the central atom is C.

So, Atomic Number of C is 6

Ground State electronic configuration:

    1s22s22p2 


Excited state

     1s22s12p3  or 1s22s12px12py12pz1

This is because, C bonds with 4 H and shares 1 electron with each of the H. So, in order to bond, 4 electrons are placed separately so that each can bond with 1 H each.
 

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As one of the p orbital of Carbon is vacant in ground state and on exciting the electron of from ground state it jumps to the higher energy level . 2p has higher energy level than 2s . So, electron jumps from 2s orbital to vacant 2p.
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what if i ask the electronic configaration of ag atomic number 47 in its excited state?
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