x=3sin theta and y=4cos theta find the value of root 16x2+9y2 Share with your friends Share 2 Vijay Kumar Gupta answered this It is given that, x=3sinθ and y=4cosθWe need to find the value of 16x2+9y2From the given hypothesis, we get x2=3sinθ2=9 sin2θ y2=4cosθ2=16 cos2θ So the required value can be calculated as, 16x2+9y2=169 sin2θ+916 cos2θ =144 sin2θ+144 cos2θ =144 sin2θ+cos2θ =144 since sin2θ+cos2θ=1 =12 14 View Full Answer Aparna Bastin answered this x2=9sin2 y2=16cos2 root16x2+9y2 =root16*9sin2+9*16cos2 =root16*9(sin2+cos2) =root 16*9*1 =root16*root9=4*3=12 3
