Moving Charges And Magnetism
Magnetic Force

Static charges produce an electric field while current or moving charges produce magnetic field (B).

Magnetic field of several sources is the vector addition of magnetic field of each individual source.
Lorentz Force

Consider a point charge q moving in the presence of both electric and magnetic fields.
Let
q − Point charge
v − Velocity of point charge
t − Time
r − Distance
B (r) − Magnetic field
E (r) − Electric field
∴ Force on the charge, = F_{electric} + F_{magnetic}
This force is called Lorentz force.

Force due to magnetic field depends on q, v, B. Force on negative charge is opposite to that of positive charge.

Magnetic force is a vector product of velocity (v) and magnetic field (B). It vanishes, if v and B are parallel or antiparallel.

Magnetic force is zero, if charge is not moving.

Unit of magnetic field (B) is tesla (T).
Magnetic force on a current carrying conductor:
A straight rod carrying current is considered.
Let
A − Crosssectional area of the rod
l − Length of the rod
n − Number density of mobile charge carriers
I − Current in the rod
v_{d} − Average drift velocity of mobile charge carrier
B − External magnetic field
Force on the carriers,
F = (nAl) qv_{d} × B
Since current density, j = nqv_{d}
∴ F = [(nqv_{d})Al] × B
F = [jAl] × B
F = I l × B
Where,
l is the vector magnitude of length of the rod

For a wire of arbitrary shape,

When a charged particle having charge q moves inside a magnetic field with velocity v, it experiences a force .

When is perpendicular to, the force on the charged particle acts as the centripetal force and makes it move along a circular path.

Let m be the mass of charged particle and r be the radius of the circular path.
Then $q\left(\overrightarrow{v}\times \overrightarrow{B}\right)=\frac{m{v}^{2}}{r}$
v and B are at right angles
$\therefore qvB=\frac{m{v}^{2}}{r}\phantom{\rule{0ex}{0ex}}\Rightarrow r=\frac{mv}{Bq}$

Time period of the circular motion of a charged particle is given by
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