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The equivalent mass of Cl2in the above reaction is
E.g: 9876543210, 01112345678
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Syllabus
H2P2O7
In all cases P = 5+ (max. value for oxidation state)
H is always 1+ (except in hydrides = -1)
So in this case Oxidation Number of O = -12/7[2+10+7x = 0 so 7x = -12 therefore x = -12/7]
AM I RIGHT, SIR? DID I FOLLOW THE RULES OF OXIDATION STATE/NUMBER
The equivalent mass of Cl2in the above reaction is
CH4 +4Cl2----->CCl4+4HCl