Solution: L.H.S = cos [ (π+π/2) +x]cos (2π+x) [cot ((π+π/2)-x) + cot (2π+x)]

= cos (π/2+x) cos (2π+x) [ cot(π/2-x) + cos(2π+x)]

= -sin x cos x [tan x + cot x] (bcz cos (π/2+x) = -sin x)

= -sin x cos x [sin x/cos x + cos x/sin x]

= -sin x cos x [sin²x+cos²x/cos x sin x]

= (-sin x cos x) [1/sin x cos x]

= -1

BUT THE CORRECT ANSWER IS 1

IN NCERT SOL. GIVEN ON MERITNATION THEY HAD TAKEN cos (π/2+x)= sin x

but correct identity is cos (π/2+x)=-sin x

which value of this identity I have to use so that I could get correct answer i.e,1and tell me how it has been used choose 1 whether cos (π/2+x)= sin x OR cos (π/2+x)=-sin x

plz help I m having exam tomorrow

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