A compound with molecular formula C4H4O has all the 4 carbons and the oxygen atom in the ring. It also has 2 double bonds. The compound is
a) Homocyclic and aromatic
b) Heterocyclic and aromatic
c) Homocyclic but not aromatic
d) Heterocyclic but not aromatic
Plz reply fast
It is cyclic system with one oxygen atom (hetero atom). So it is heterocyclic.
2 double bond presents having 2X2 = 4 π electrons
To be aromatic (4n+2) π electrons is needed.
When n=0, (4n+2) = 2
When n=1, (4n+2) = 6
Taking one of the two loan pair of electron of oxygen, total π electron becomes 6 and it becomes aromatic, which is more stable.
Thus the compound is heterocyclic aromatic compound.
2 double bond presents having 2X2 = 4 π electrons
To be aromatic (4n+2) π electrons is needed.
When n=0, (4n+2) = 2
When n=1, (4n+2) = 6
Taking one of the two loan pair of electron of oxygen, total π electron becomes 6 and it becomes aromatic, which is more stable.
Thus the compound is heterocyclic aromatic compound.