a narrow glass tube 80 cm long and opens at both the ends is half immersed in mercury now the - Physics - Kinetic Theory

Question

a narrow glass tube 80 cm long and opens at both the ends is
half immersed in mercury now the top of the tube is closed and is
taken out of mercury a 20cm long mercury column remains in the tube
find atmospheric pressure??
plz gv a detailed explanation

Neha Gupta · Accepted Answer

We know pressure exerted due to mercury is given by:p = hρgwhere ρ is the density of the mercuryand h is the height of the mercury in the tube
Rise of the mercury in the tube is equal to the atmospheric pressure 
h = 20 cm = 0
20 mρ = 5
43 g/cm3ρ = 5430 kg/m3g = acceleration due to gravityg = 9
8 m/s2p = 0 2×5430×9
8p = 10642 8 pascal

a narrow glass tube 80 cm long and opens at both the ends is half immersed in mercury now the top of the tube is closed and is taken out of mercury . a 20cm long mercury column remains in the tube . find atmospheric pressure?? plz gv a detailed explanation

a narrow glass tube 80 cm long and opens at both the ends is half immersed in mercury now the top of the tube is closed and is taken out of mercury . a 20cm long mercury column remains in the tube . find atmospheric pressure??

plz gv a detailed explanation