If log K = 6.134 then K = 1.36X 106. How?

log K =6.134
K = A.log(6.134)     = A.log(0.134) × 106     = 1.36 × 106

  • 0
it needs to be calculated using logarithmic tables or a calculator. If it's asked in the exam, a value will be provided which will help you get the value directly. :)
  • 0
What are you looking for?