In the figure, the blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. F1 and F2 are external forces of magnitudes 2 mg and mg respectively.
(A) ​a1 = a2 = a3            (B) ​a> a2 > a3               (C) ​a= a2, a2 > a3           (D) ​a> a2, a= a3 

Dear Studemt,

for fig 12mg-mg=ma1a1=gfor fig 22mg-mg=ma2a2=gfor fig 3mg-mg=ma3a3=0hence a1=a2, a2>a3 option C Regards 

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