In the figure, the blocks A, B and C of mass m each have acceleration a1, a2 and a3 respectively. F1 and F2 are external forces of magnitudes 2 mg and mg respectively. (A) a1 = a2 = a3 (B) a1 > a2 > a3 (C) a1 = a2, a2 > a3 (D) a1 > a2, a2 = a3 Share with your friends Share 0 Shobhit Mittal answered this Dear Studemt, for fig 12mg-mg=ma1a1=gfor fig 22mg-mg=ma2a2=gfor fig 3mg-mg=ma3a3=0hence a1=a2, a2>a3 option C Regards -8 View Full Answer