In the figure given below, AB || DC || EF, AD || BC and ED || FA. Prove that: Area of DEFH = Area of ABCD

no 12 a) Q12.(a) In the figure (1) given below, ABCD and AEFG are two parallelograms. Prove that area of || gm ABCD = area of || gm AEFG.

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Ans:32cm2

Please don't send me any links...

ANS: 192cm2.

10. In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC.

IF BH is perpendicular is FG, prove that :

(ii) Area of the square ABDE = Area of the rectangle ARHF.

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9.In the given figure, AP is parallel to BC, BP is parallel to CQ. Prove that the areas of triangles ABC and BQP are equal.Q.6. In the figure given below, ABC is an equilateral triangle in which P and S are the mid-points of arcs AB and AC respectively. Prove that: PQ = QR = RS.

the length of BD.

b. In figure.ii.given below, angle PSR=90?,PQ=10cm,QS=6cm and R Q=9cm. Calculate the length of PR.

c. In figure.iii. given below, angle D=90?,AB=16cm,BC=12cm and CA=6cm .Find CD.

In the figure given below, AB || DC || EF, AD || BC and ED || FA. Prove that: Area of DEFH = Area of ABCD

i) Area of triangle AGB = 2/3 * Area of triangle ADB

ii) Area of triangle ABG = 1/3 * Area of triangle ABC

no 12 a)

Q12.(a) In the figure (1) given below, ABCD and AEFG are two parallelograms. Prove that area of || gm ABCD = area of || gm AEFG.

Area of traingle (ADC = AEB)

Area of traingle (BOD = COE)