1.01% of aqueous solution of KNO3 is  90% dissociated at 300K. Calculate its osmotic pressure.

Dear Student,

We know that, π=iCRTi=1+α(n-1)For KNO3, n=2and, α=0.90So, i=1+0.90(2-1) =1+0.90 =1.90R=0.0821 Latmmol-1K-1C=1.01 %T=300 Kπ=1.90×1.01×0.0821×300   =47.26 atm

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