1.6 gm of metal were disolved in HNO3 to prepare its nitrate. The nitrate on strong heating gives 2 gm oxide . The eq. Wt of metal is ??

Mass of metal = 1.6 g
Mass of metal oxide produced = 2 g
Therefore, mass of oxygen in the oxide = 2 - 1.6 = 0.4 g
Now,
equivalent weight of metal = (mass of metal/ mass of oxygen ) x 8
  = (1.6/0.4) x 8
  = 32

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