10 chem que.

S o l u t i o n T h e d i s \tan c e b e t w e e n t h e a d j a c e n t l a y e r s i s = r \times 2 \sqrt{\frac{2}{3}} = 250 \times 2 \sqrt{\frac{2}{3}} = 500 \sqrt{\frac{2}{3}} = 408 p m

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