12 Calculate the equilibrium constant for the redox reaction at 25 C Fe2+ + Ce4+ → Fe3+ + - Chemistry - Electrochemistry

Question

12   Calculate   the   equilibrium   constant
  for   the   redox   reaction   at  
25 °   C Fe 2 +   +   Ce 4 +   →
  Fe 3 +   +   Ce 3 +   given   E ° Ce
4 + / Ce 3 + = 1 42   V   and   E ° Fe 3 + / Fe
2 + = 0 77 V

Megha Sharma · Accepted Answer

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12 . Calculate the equilibrium constant for the redox reaction at 25 ° C . Fe 2 + + Ce 4 + → Fe 3 + + Ce 3 + given E ° Ce 4 + / Ce 3 + = 1 . 42 V and E ° Fe 3 + / Fe 2 + = 0 . 77 V .

$12 . Calculate the equilibrium constant for the redox reaction at 25 ° C . {Fe}^{2 +} + {Ce}^{4 +} \to {Fe}^{3 +} + {Ce}^{3 +} given E °_{Ce 4 + / Ce 3 +} = 1.42 V and E °_{Fe 3 + / Fe 2 +} = 0.77 V .$