13th. pls dont send any links

Q13) Find the coefficient of  x 7   in   a x   +   1 b x 11   and   x - 7   in   a x   - 1 b x 2 11  and find the relation between a and b so that coefficients are equal .

Dear student

We know that r+1th term in the expansion of x+an is given by:Tr+1=nCr xn-r arWe have ax+1bx11Let x7 occur in r+1th term, henceTr+1=11Crax11-r1bxr=11Cra11-rbrx11-rxr=11Cra11-rbrx11-2rAs this term contains x711-2r=74=2rr=2Hence the coefficient of x7 in  ax+1bx11Coefficient of x7=11C2a11-2b2Coefficient of x7=11C2a9b2ax-1bx211



=11C6a5b6Given:Coefficient of x7 in ax+1bx11=Coefficient of x-7 in ax-1bx21111C2a9b2=11C6a5b655×a4=462b4   as nCr=n!r!n-r!a4b4=46255ab4=425ab=42514
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