13th. pls dont send any links Q13) Find the coefficient of x 7 in a x + 1 b x 11 and x - 7 in a x - 1 b x 2 11 and find the relation between a and b so that coefficients are equal . Share with your friends Share 0 Neha Sethi answered this Dear student We know that r+1th term in the expansion of x+an is given by:Tr+1=nCr xn-r arWe have ax+1bx11Let x7 occur in r+1th term, henceTr+1=11Crax11-r1bxr=11Cra11-rbrx11-rxr=11Cra11-rbrx11-2rAs this term contains x7⇒11-2r=7⇒4=2r⇒r=2Hence the coefficient of x7 in ax+1bx11Coefficient of x7=11C2a11-2b2⇒Coefficient of x7=11C2a9b2ax-1bx211 =11C6a5b6Given:Coefficient of x7 in ax+1bx11=Coefficient of x-7 in ax-1bx21111C2a9b2=11C6a5b655×a4=462b4 as nCr=n!r!n-r!a4b4=46255ab4=425ab=42514 Regards 1 View Full Answer Praveen Singh answered this Please find this answer 1