2 boys weighing 40 kg and 50 kg are sitting on either sides of a wooden plank at distances 4.5m and 1.5m respectively feom the fulcrum coinciding with the centre of gravity of the plank. Where must a third boy of weight 35kg sit to secure balance?

Dear student
Let 40 kg boy sits on the left of the fulcrum than torque of its weight about the fulcrum in anticlockwise direction isT1 =40×10×4.5=1800NmLet 50 kg boy sits on the right of the fulcrum than torque of its weight about the fulcrum in clockwise direction isT2=50×10×1.5=750NmAnticlockwise torque is greater than the clockwise torque so the other boy must sit to provide clockwise torque so it should sit right of fulcrum.Let the boy sits at a distance xfrom thefulcrumthan the torque of its weight about thefulcrum is T3=35×10×xFor equibrium clockwise torque=anticlockwise torque50×10×1.5+35×10×x=40×10×4.550×1.5+35×x=40×4.575+35x=18035x=180-7535x=105x=10535=3mRegards

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3 metres from the fulcrum in the direction of 40 kg.

Use principle of moments
 
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