200cm3 of an aqueous solution of a protein contains 1.26 gm of a protein. The osmotic pressure of such a solution at 300K is found to be 2.57 * 10-3 bar. Calculate the molar mass of the protein.

Dear User,
According to Van't Hoff equation,
π=cRT   = nVRT   = wBRTMBVMB = wBRTπVV = 200 cm3=0.20 L, wB = 1.26 g , T= 300 K, R= 0.083 LbarK-1mol-1 , π=2.57×10-3 barTherefore, MB = 1.26×0.083×3002.57×10-3×0.20                          = 61039 gmol-1

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