23 .   I f   e q u a t o r i a l   p l a n e   i n   P C l 3   m o l e c u l e   i s   t h e   X - Y   p l a n e   t h e   o r b i t a l s   h y b r i d i z i n g   t o   p r o d u c e   a x i a l           b o n d s   w i l l   b e : A   p z                                                                                                   B   d y 2 C   p y                                                                                                   D   d z 2

Dear student
The molecule should be PCl​5 since PCl3 is having pyramidal geometry which does not has equatorial plane.
Axial bonds are perpendicular to equatorial plane, hence the orbitals hybridizing axial bonds will be pz and dz2.
Answer will be A and D.

Hope it helps
Regards

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