34 In the figure shown, the friction coefficient between the block of mass 1 kg and plank of - Physics - Laws Of Motion

Question

34 In the figure shown, the friction coefficient between the block
of mass 1 kg and plank of mass 2 kg is 0 4 while that between the
plank and floor is 0 1 a constant force F start acting horizontally
on the upper 1 kg block The acceleration of plank if F = 10 N
is
A )     10 3 m / s 2           B
)     7 3 m / s 2          
          C )     0 5   m /
s 2                 D )
    1 0   m / s 2

Sanjay Singh · Accepted Answer

Dear student

1)  Limiting friction on the plank by the ground which is in backward direction  is f1=μ1N1=0
1×3×10=3N2)Limiting friction on the upper surface of the plank which acts on it in the forward direction is by the block is f2=μ2N2=0
4×1×10=4N3)Net force on the plank in the forward direction is Fnet=4-3=1ma=1a=12=0
5m/s2Regards