39 A car moving at a constant velocity of 46 m/s passes a traffic cop who is readily sitting - Physics - Laws Of Motion

Question

39 A car moving at a constant velocity of 46 m/s passes a traffic
cop who is readily sitting on his motorcycle After a reaction time
of 1 0 s, the cop begins to chase the speeding car with a constant
acceleration of 4 0 m/s2 How much time does the cop then
need to overtake the speeding car?

Vipra Mishra · Accepted Answer

Dear Student

Let the cop overtake speeding car in t seconds
Distance covered by cop in t second is equal to distance covered by
car in t-1 second as cop started after 1 second
Distance covered by car s =v (t-1)= 46 (t-1)Distance covered by copes = ut +12 at2s=0+12 4t2= 2t2When cop catches speeding car46 (t-1)=2t22t2-46t +46 =0t2-23t +23 =0t = 22 sec or 1 secAs 1 sec is not possible so t =22 sec

39. A car moving at a constant velocity of 46 m/s passes a traffic cop who is readily sitting on his motorcycle. After a reaction time of 1.0 s, the cop begins to chase the speeding car with a constant acceleration of 4.0 m/s2. How much time does the cop then need to overtake the speeding car?

39. A car moving at a constant velocity of 46 m/s passes a traffic cop who is readily sitting on his motorcycle. After a reaction time of 1.0 s, the cop begins to chase the speeding car with a constant acceleration of 4.0 m/s². How much time does the cop then need to overtake the speeding car?