4) If two resistance of values R1=(2 0 + 0 1)ohm, R2 = ( 12 3 +-0 2)ohm are out - Physics - Units And Measurements

Question

4) If two resistance of values R1=(2 0 + 0 1)ohm,
R2 = ( 12 3 +-0 2)ohm are out in (i) in
series (ii) parallel Find the error in the equivalent resistance

Jyoti Pant · Accepted Answer

R1=2 0±0 1 ohmR2=12 3±0
2 ohmSeries combination:R=R1+R2=2 0+12 3=14
3 ohm∆R=±[ ∆R1+∆R2]=±[0
1+0 2]=±0 3 ohmSo, R=[14 3±0
3] ohmParallel combination:1R'=1R1+1R2=12 0+112 3=12 3+2
024 6=14 324 6or R'=24 614 3=1
72 ohm∆R'R'2=∆R1R12+∆R2R22Or ∆R'=∆R1 [R'R1]2+∆R2[ R'R2]2=0
1×[24 614 3×2]2+0 2 ×[24 614 3×12
3]2=0 1×[12 314 3]2+0 2×[214 3]2=15 129204 49+0 8204
49=15 929204 49=0 78Thus, R'=[1 72±0 78] ohm

4) If two resistance of values R1=(2.0 + 0.1)ohm, R2 = ( 12.3 +-0.2)ohm are out in (i) in series (ii) parallel.Find the error in the equivalent resistance.

4) If two resistance of values R₁=(2.0 + 0.1)ohm, R₂ = ( 12.3 +_-0.2)ohm are out in (i) in series (ii) parallel.Find the error in the equivalent resistance.