44) The period of revolution of a satellite orbiting Earth at a height 4R above the surface of Earth is x hrs. where R is the radius of earth. The period of another satellite at a height 1.5 R from the surface of the Earth is.
$$\begin{gathered} \left(1\right) \frac{x}{2\sqrt{2}}hrs \\ \left(2\right) \frac{x}{\sqrt{2}}hrs \\ \left(3\right) \sqrt{2}x hrs \\ \left(4\right) \frac{x}{2}hrs \end{gathered}$$