Dear student ϕ:C→Rxϕy gives x=yNow, let z=x+iy then z=x2+y2Consider 2+3i=22+32=13≠133≠-3and 1+i=12+12=2≠2and i=1So, i,1∈ϕHence correct option is iϕ1 Regards

7th.one asap

7th.one asap one 8. Let R be a relation on N defined by 2 y R (a) 4.81 12, 9, R is a relation from 11, 12, 12 | defined (a) 11), (10, (d) none 01 these. (c) I (10.13). (8, 11), (12.10) If the set A has elements, B has q elements, then the number (c) pq 11. Let R bea relation from a set A to a set B, then (d) R c BOA. (c) RGA*B 12. If R is a relation from a finite set A having m elements toa finite set B having' then the number of relations from A to B is

Dear student

ϕ : C \to R xϕy gives |x| = y Now, let z = x + iy then |z| = \sqrt{x^{2} + y^{2}} Consider |2 + 3 i| = \sqrt{2^{2} + 3^{2}} = \sqrt{13} \neq 13 |3| \neq - 3 and |1 + i| = \sqrt{1^{2} + 1^{2}} = \sqrt{2} \neq 2 and |i| = 1 So, (i, 1) \in ϕ Hence correct option is iϕ 1

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