A 10 kg body is suspended by a weightless spring force constant is 250 N per m .if the body is displaced downwards by 40 cm determine the time period , maximum speed of the body , total energy of spring body system.

Dear Student,
​​​​​​Mass = 10 Kg
K= 250 N/m 
Amplitude = A = 40 cm = 0.4 m

ω=km=25010=25=5 rad/sT=2πω=2π5=1.25 sec
Maximum Speed of the Body,Vmax =Aω=(0.4)5=2m/s
Total Energy of the body, TE = KEmax=12m(Vmax)2=1210(2)2=20 J
Thus,
Time Period = 1.25 sec
Maximum Speed = 2 m/s
Total Energy = 20 J

Regards
 

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