a 2 kg body is dropped from a height of 1 m onto a spring of spring constant 800 N/m - Physics - Work Energy And Power

Question

a 2 kg body is dropped from a height of 1 m onto a spring of spring
constant 800 N/m a frictional force of 0 4 kg-wt acts on the body
the speed of the body junst before striking the spring will be

Sushant · Accepted Answer

Dear student,

Please find below the solution to the asked query:

As the body is under free fall,the net force in downward direction = weight of the body = 20Nwhile the net force due to friction in the upward direction  = 0
4 ×10  =4 Nthus the net downward force = 20 - 4 = 16 Nhence the net downward accelerartion of the body  = 16/2  = 8 m/s2thus after falling a height of 1 m,its velocity will bev2  = u2 +2asas u = 0so v = 2as = 2×8×1  = 4 m/sthis is the speed of the ball before striking the spring

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a 2 kg body is dropped from a height of 1 m onto a spring of spring constant 800 N/m a frictional force of 0.4 kg-wt acts on the body. the speed of the body junst before striking the spring will be