a ball is dropped from a building of height 45m . simultaneously another ball is thrown up with a speed of 40m/s. calculate the relative speed of balls as a function of time.

The speed of a ball dropped a height of 45m after time is given byv1=gt---1Second ball thrown up with velocity 40 ms-2, will possess velocity v2in time t is given byv2=40-gt---2For relative velocity , these two velocities are opposite to each other, so velocities will be added,i.e.v1+v2=gt+40-gt=40ms-1.

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