A ball is dropped from a building of height h. Simultaneously another ball is thrown up from the ground with a velocity such that it can reach upto a height 5h. Find the time at which the two balls would cross each other.

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Try solving the question relatively.
Or use S=u+1/2at^2 two times. And solve for t (time). I've got a trick to solve this question. And you'll be able to answer it in 5seconds. Follow me for more:) Cheers!
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