A ball of mass 200g moving with a velocity of 25 m/s is struck by the batsman to return along - Physics - Laws Of Motion

Question

A ball of mass 200g moving with a velocity of 25 m/s is struck by
the batsman to return along the same path in opposite direction
with the same speed the collision of the ball with bat lasts for 0
5 sec find the impulse of the force and tge average force of impact

Sayantan · Accepted Answer

Dear Student,

Initial velocity= u
final velocity= -u

Change in momentum= m(u-(-u)) = 2mu

2×0
2×25⇒10 Kg-m/s ( N-s)Force= Rate of change in momentumF=0
2×2×250 5⇒20 N

Regards

A ball of mass 200g moving with a velocity of 25 m/s is struck by the batsman to return along the same path in opposite direction with the same speed . the collision of the ball with bat lasts for 0.5 sec find the impulse of the force and tge average force of impact