A block of mass m is moving with speed v on a wedge of mass M which is placed upon a horizontal surface. Track AB is a circular track of radius R. What is the minimum speed v so that the block reaches point A

Dear Student,

Initially the wedge is stationary but the wedge is not fixed so when the block moves on the wedge it will transfer some of its energy to wedge.

Also, at highest point (for minimum speed of block) the speed of block will be equal to that of wedge. It is because if it is more than it is not minimum speed and if it is less it can not move to the highest point and will loose contact from the surface in between the path.

This is why we consider both the speed of wedge and block at the highest point and equal.

Regards,

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My question is that why are we taking m+M in the conservation of kinetic energy...Even when the mass M is stationary and not moving

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