A body of mass 4 kg is placed on a smooth inclined plane of inclination 60 degree.The horizontal force to be applied to make the body move up the plane with an acceleration 2m/s2

Dear student,
The force required to move the block upwards with acceleration 2m/s² will be against the force of gravity. As the surface is inclined so the component of the gravity in downward direction will be $g\sin \theta$
$$\begin{gathered} So F= m(g\sin \theta -a) \\ =4(9.8\times 0.86 -2) \\ = 4\times 6.4 \\ =25.6N \end{gathered}$$ Regards