a car starts from rest and accelerates uniformly with 2 m/s. At t= 10s a stone is dropped out of the window of the car which is 1 m in height from the ground what will be the velocity and acceleration of the stone at t= 10 s neglect air resistance . (g=10 m/s2)
as the car accelerates with the magnitude of 2m/s^2 at 10 sec it's speed will be 10*2m/s; i.e 20m/s and at that time if the stone is dropped it will be no more under horizontal acceleration therefore its velocity at 10 sec will be 20m/s
