A compound contains X,Y AND Z atoms .the oxidation states of X , Y AND Z are +2 ,+2 and -2 respectively. the possible formula of the compound is a) XYZ2 b) X3(Y4Z)2
Dear Student,
X, Y and Z forms a neutral compound. So sum of oxidation number of X, Y and Z should be equal to the zero.
Oxidation number of X, Y and Z are +2 , +2, -2 respectively.
a) XYZ2
sum of oxidation number of X, Y and Z in XYZ2
(+2 ) + (+2) +2(-2) = 0
4 -4 = 0
0 =0
So, XYZ2 is the correct formula.
b) X3(Y4Z)2
sum of oxidation number of X, Y and Z in X3(Y4Z)2
3(+2) + 2(4(+2)+(-2))=0
6 +2(8-2) =0
18 = 0
Since LHS is not equal to RHS so the formula X3(Y4Z)2 is incorrect.
Regards
X, Y and Z forms a neutral compound. So sum of oxidation number of X, Y and Z should be equal to the zero.
Oxidation number of X, Y and Z are +2 , +2, -2 respectively.
a) XYZ2
sum of oxidation number of X, Y and Z in XYZ2
(+2 ) + (+2) +2(-2) = 0
4 -4 = 0
0 =0
So, XYZ2 is the correct formula.
b) X3(Y4Z)2
sum of oxidation number of X, Y and Z in X3(Y4Z)2
3(+2) + 2(4(+2)+(-2))=0
6 +2(8-2) =0
18 = 0
Since LHS is not equal to RHS so the formula X3(Y4Z)2 is incorrect.
Regards