a current of 9.65 A flowing for 10 minutes deposits 3 g of a metal . the equivalent weight of metal is

Wt. of metal deposited=3.0g
Q=i X t
=9.65 X 10 X 60
=5790C
Eq.wt. of metal= Wt. of metal​ X 96500
                                     Q
                         =     3     X 96500
                             5750
                        =50.34
                        =50(approx.)