A first order reaction is 50% complete in 30 minutes at 27° C and in 10 minutes at 47 ° C.calculate the activation energy.

It is a first order reaction and reaction is 50% completed (that is half life period) in 30 min at 27⁰C and in 10 min at 47⁰C

From this we can calculate k₁ and k₂.

k₁  = 0.693/t_1/2 at 27⁰C

 = 0.693 / 30 = 0.0231

k₂ = 0.693/t_1/2 at 47⁰C

 =  0.693 / 10 

 = 0.0693

T₁ = 273 + 27 = 300K

T₂  = 273 + 47  = 320K

After putting all the values in the given formula you will get the value of activation energy.