A first order reaction is 50% complete in 36min at 300K. the same reaction is 50% complete in 9min at 350K. calculate activation energy of the reaction.
k = 0.693 / t 1/2
k1 = 0.693 / 36 = 0.01925 min -1
k2 = 0.693 / 9 = 0.077 min -1
log k2 / k1 = Ea / 2.303R (1/T1 - 1/T2) {T1 = 300k , T2 = 350k , R = 8.314 JK-1 mol-1}