A loco engine of mass 40 ton moves on a straight track having nu 0.01. When speed is 72kmh power developed by engine is 880 kW.its acceleration at that instant is. G 10ms
Dear student,
F.V=P
》F=P/V =[(880×103)/20] =44×103 N
and
F/m = (44×103)/(40×103) = 1.1 m/s2
now acceleration is
a= [(F/m)-μg ] = [1.1 - (0.01×10) ]=(1.1-0.1) = 1 m/s2
Regards.
F.V=P
》F=P/V =[(880×103)/20] =44×103 N
and
F/m = (44×103)/(40×103) = 1.1 m/s2
now acceleration is
a= [(F/m)-μg ] = [1.1 - (0.01×10) ]=(1.1-0.1) = 1 m/s2
Regards.