A metal has bcc structure and the edge length of its unit cell is 3.04 A. The volume of the unit cell in cm^3 will be ?
Dear Student,
The element crystallises into BCC structure. So, number of atoms per unit cell = 2 (Z)
Edge length of BCC structure = 3.04 Angstrom
Edge length of BCC structure in cm = 3.04 X 10-8 cm
Volume of the unit cell in cm3 = (Edge length )3
Volume of the unit cell in cm3 = ( 3.04 X 10-8 cm)3 = 28 .09 X 10-24 cm3 = 2.809 X 10-23 cm3
Regards
The element crystallises into BCC structure. So, number of atoms per unit cell = 2 (Z)
Edge length of BCC structure = 3.04 Angstrom
Edge length of BCC structure in cm = 3.04 X 10-8 cm
Volume of the unit cell in cm3 = (Edge length )3
Volume of the unit cell in cm3 = ( 3.04 X 10-8 cm)3 = 28 .09 X 10-24 cm3 = 2.809 X 10-23 cm3
Regards